Help with some % calculations

[rafael.compassi]

Hello Tom, Biollante and fellow users!

Could you guys help me with some math?

I have found a local supply of chelated nutrientes, of the following composition (in %):

B 0,7
Cu 0,3
Fe 7,5
Mn 3,4
Mo 0,1
Zn 0,6

This product have roughly 1.5 to 2x the concentration of the CSM+B (except for the Fe).

What would be the % concentrations if I mix it half and half with Fe Edta?

The B would need a bump too, Should I mix a little boric acid too? How much?

(Mind that I'm trying to make something similar to the concentrations of the CSM+B)

I really apreciate some help with this, guys!

Tanks!

Rafael

 

[Biollante]

Looks About the Same to Me

Hi Rafael,

Your trace mix is approximately the same as CSM+B.

• the Molybdenum is 10 times greater.
• The Copper is 3 times greater in your mix.
  
• The Manganese is 41% greater in your mix.
  
• The Zinc is 30% greater in your mix
  
• The Iron is 6.3% greater in your mix.
• The Boron is 12.5% less in your mix.
  

Adding half again as much 10% chelated Iron as CSM+B will add about 75% more Iron.


I do not think the Boron makes much difference, over the last few months I have been looking at different levels and I cannot discern any growth differences so far.

• To be sure though adding 46 grams of Borax in 1 liter solution with distilled water
  
• will yield about 0.5% Boron solution so
  
• adding 1 milliliter of 0.5% Boron solution for every gram of CSM+B will yield about 5:1 Iron:Boron that Tom Barr recommends.
  

I do not see any real problem with mix you have compared to CSM+B as long as it is highly chelated.


Biollante